\(\int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx\) [37]

Optimal result

Integrand size = 16, antiderivative size = 16 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\text {Int}\left (\frac {\text {csch}^3(a+b x)}{(c+d x)^2},x\right ) \]

[Out]

Unintegrable(csch(b*x+a)^3/(d*x+c)^2,x)

Rubi [N/A]

Not integrable

Time = 0.03 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx \]

[In]

Int[Csch[a + b*x]^3/(c + d*x)^2,x]

[Out]

Defer[Int][Csch[a + b*x]^3/(c + d*x)^2, x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 69.35 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.12 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx \]

[In]

Integrate[Csch[a + b*x]^3/(c + d*x)^2,x]

[Out]

Integrate[Csch[a + b*x]^3/(c + d*x)^2, x]

Maple [N/A] (verified)

Not integrable

Time = 0.22 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.00

\[\int \frac {\operatorname {csch}\left (b x +a \right )^{3}}{\left (d x +c \right )^{2}}d x\]

[In]

int(csch(b*x+a)^3/(d*x+c)^2,x)

[Out]

int(csch(b*x+a)^3/(d*x+c)^2,x)

Fricas [N/A]

Not integrable

Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.81 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int { \frac {\operatorname {csch}\left (b x + a\right )^{3}}{{\left (d x + c\right )}^{2}} \,d x } \]

[In]

integrate(csch(b*x+a)^3/(d*x+c)^2,x, algorithm="fricas")

[Out]

integral(csch(b*x + a)^3/(d^2*x^2 + 2*c*d*x + c^2), x)

Sympy [N/A]

Not integrable

Time = 0.54 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.94 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int \frac {\operatorname {csch}^{3}{\left (a + b x \right )}}{\left (c + d x\right )^{2}}\, dx \]

[In]

integrate(csch(b*x+a)**3/(d*x+c)**2,x)

[Out]

Integral(csch(a + b*x)**3/(c + d*x)**2, x)

Maxima [N/A]

Not integrable

Time = 0.67 (sec) , antiderivative size = 545, normalized size of antiderivative = 34.06 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int { \frac {\operatorname {csch}\left (b x + a\right )^{3}}{{\left (d x + c\right )}^{2}} \,d x } \]

[In]

integrate(csch(b*x+a)^3/(d*x+c)^2,x, algorithm="maxima")

[Out]

-((b*d*x*e^(3*a) + (b*c - 2*d)*e^(3*a))*e^(3*b*x) + (b*d*x*e^a + (b*c + 2*d)*e^a)*e^(b*x))/(b^2*d^3*x^3 + 3*b^
2*c*d^2*x^2 + 3*b^2*c^2*d*x + b^2*c^3 + (b^2*d^3*x^3*e^(4*a) + 3*b^2*c*d^2*x^2*e^(4*a) + 3*b^2*c^2*d*x*e^(4*a)
+ b^2*c^3*e^(4*a))*e^(4*b*x) - 2*(b^2*d^3*x^3*e^(2*a) + 3*b^2*c*d^2*x^2*e^(2*a) + 3*b^2*c^2*d*x*e^(2*a) + b^2
*c^3*e^(2*a))*e^(2*b*x)) - 8*integrate(1/16*(b^2*d^2*x^2 + 2*b^2*c*d*x + b^2*c^2 - 6*d^2)/(b^2*d^4*x^4 + 4*b^2
*c*d^3*x^3 + 6*b^2*c^2*d^2*x^2 + 4*b^2*c^3*d*x + b^2*c^4 + (b^2*d^4*x^4*e^a + 4*b^2*c*d^3*x^3*e^a + 6*b^2*c^2*
d^2*x^2*e^a + 4*b^2*c^3*d*x*e^a + b^2*c^4*e^a)*e^(b*x)), x) - 8*integrate(-1/16*(b^2*d^2*x^2 + 2*b^2*c*d*x + b
^2*c^2 - 6*d^2)/(b^2*d^4*x^4 + 4*b^2*c*d^3*x^3 + 6*b^2*c^2*d^2*x^2 + 4*b^2*c^3*d*x + b^2*c^4 - (b^2*d^4*x^4*e^
a + 4*b^2*c*d^3*x^3*e^a + 6*b^2*c^2*d^2*x^2*e^a + 4*b^2*c^3*d*x*e^a + b^2*c^4*e^a)*e^(b*x)), x)

Giac [F(-1)]

Timed out. \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\text {Timed out} \]

[In]

integrate(csch(b*x+a)^3/(d*x+c)^2,x, algorithm="giac")

[Out]

Timed out

Mupad [N/A]

Not integrable

Time = 0.91 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.12 \[ \int \frac {\text {csch}^3(a+b x)}{(c+d x)^2} \, dx=\int \frac {1}{{\mathrm {sinh}\left (a+b\,x\right )}^3\,{\left (c+d\,x\right )}^2} \,d x \]

[In]

int(1/(sinh(a + b*x)^3*(c + d*x)^2),x)

[Out]

int(1/(sinh(a + b*x)^3*(c + d*x)^2), x)